If cosec (A-20°)=sec 4A where 20°<A and 4A is an acute angle then find the value of A?
Answers
Answered by
8
Hi , there !!
cosec ( A -20 ° ) = sec4 A
sec 4 A= Cosec ( 90 -4 A )
on equating we get the
Cosec ( A -20 ) = Cosec ( 90 -4 A )
=> A -20° = 90° -4A
=> 5A = 110°
=> 22 °
where A< 90°
hope it helps !!
thanks !!
ranjan kumar
cosec ( A -20 ° ) = sec4 A
sec 4 A= Cosec ( 90 -4 A )
on equating we get the
Cosec ( A -20 ) = Cosec ( 90 -4 A )
=> A -20° = 90° -4A
=> 5A = 110°
=> 22 °
where A< 90°
hope it helps !!
thanks !!
ranjan kumar
Raj16739:
Yes
Answered by
1
cosec(A-20°) = sec4A
that means
1/sin(A-20°) = 1/cos4A
therefore , sin(A-20°) = cos4A
we know that cosA = sinA when A=45°
4A = 45 , that is , A=45/4= 11.25°
A-20° = 45 , so A= 45+20= 65
here we have 2 solutions, but in the condition above it is given that A is greater than 20° , so the answer is 65°
that means
1/sin(A-20°) = 1/cos4A
therefore , sin(A-20°) = cos4A
we know that cosA = sinA when A=45°
4A = 45 , that is , A=45/4= 11.25°
A-20° = 45 , so A= 45+20= 65
here we have 2 solutions, but in the condition above it is given that A is greater than 20° , so the answer is 65°
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