If
cosec A=5/3, then find the value of
Cos A
Answers
Answered by
0
Answer:
cosec A = 5/3
h= 5 p= 3
using phytagoras theorem
h^2 = p^2 + b^2
b^2 = h^2 - p^2
= (5)^2 - (3)^2
= 25 - 9
= 16
b^2 =16
b = 4
Cos A = b/h
= 4/5
Answered by
4
HEY Mate...!!!
Answer:
cos A= 4/5
Step-by-step explanation:
Here,
cosec A=5/3
W.K.T.
cosec A= Hypotenuse/Perpendicular= H/P
so, H=5
P=3
By Pythagoras theorem,
H²=P²+B²
(5)²=(3)²+B²
25=9+B²
B²=25-9=16
B=√16
B=4
Now,
cos A= Base/Hypotenuse= B/H
cos A= 4/5
Hope it helps.....mark as brainliest (I u like to)
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