Math, asked by Nallanisivarani, 10 months ago

If
cosec A=5/3, then find the value of
Cos A​

Answers

Answered by pushkart3
0

Answer:

cosec A = 5/3

h= 5 p= 3

using phytagoras theorem

h^2 = p^2 + b^2

b^2 = h^2 - p^2

= (5)^2 - (3)^2

= 25 - 9

= 16

b^2 =16

b = 4

Cos A = b/h

= 4/5

Answered by Anonymous
4

HEY Mate...!!!

Answer:

cos A= 4/5

Step-by-step explanation:

Here,

cosec A=5/3

W.K.T.

cosec A= Hypotenuse/Perpendicular= H/P

so, H=5

P=3

By Pythagoras theorem,

H²=P²+B²

(5)²=(3)²+B²

25=9+B²

B²=25-9=16

B=√16

B=4

Now,

cos A= Base/Hypotenuse= B/H

cos A= 4/5

Hope it helps.....mark as brainliest (I u like to)

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