if cosec(A+B)=1 and Sec(A-B)=2 evaluate SinAcosB+CosAsinB
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Answered by
6
put cosec=sec(90-a-b)
and. solve by using the trignometric table
Answered by
6
Heya©®©®©®©®
_______________________________
Sin A × Cos B + Cos A × Sin A =
Sin ( A + B )
_______________________________
Cosec ( A + B ) = Cosec ( 90 )
=>
A + B = 90°
=>
Sin ( A + B ) = Sin ( 90 ) = 1
_______________________________
Sin A × Cos B + Cos A × Sin A =
Sin ( A + B )
_______________________________
Cosec ( A + B ) = Cosec ( 90 )
=>
A + B = 90°
=>
Sin ( A + B ) = Sin ( 90 ) = 1
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