If cosec (a+b)=1,cot (a-b)=root3find the values of a and b
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Hiii , I try to solve your problem .
now cosec (a+b) =1
so (a+b) =cosec inverse 1
we know that cosec inverse 1is equal to 90 .
so a+b = 90 .................1
and cot inverse root 3 is equal to 30 .
so, a-b =30 ..................2
by solving 1 and 2 we get ,
2a = 120
a = 60
put the value of a in 1 we get,
b = 30
I hope it will help you and reply me.
now cosec (a+b) =1
so (a+b) =cosec inverse 1
we know that cosec inverse 1is equal to 90 .
so a+b = 90 .................1
and cot inverse root 3 is equal to 30 .
so, a-b =30 ..................2
by solving 1 and 2 we get ,
2a = 120
a = 60
put the value of a in 1 we get,
b = 30
I hope it will help you and reply me.
aashalohchab:
hii
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