If cosec (a-b)=2,cot (a+b)=1÷squareroot3,0 <(a+b)b.find the values of a and b
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Given cot(a+b)=1/under root 3
Cosec(a-b)=2
But we know that cosec 30 =2
Therefore a-b=30
And cot 60=1/root under 3 therefore a+b=60
Solving eqn we get a=45 b=15
Cosec(a-b)=2
But we know that cosec 30 =2
Therefore a-b=30
And cot 60=1/root under 3 therefore a+b=60
Solving eqn we get a=45 b=15
Answered by
2
Answer:
45 15
Step-by-step explanation:
Hope's it helps you
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