Question

If cosec A- cot A= 2 then value of 2 cot A-5 cos A + sin A is equal to
23/2*k
then the value of K is:​

Answer 1

Answer:

-37/10

Step-by-step explanation:

cosecA-cotA = 2

we know,

cosec²A - cot²A = 1

(cosecA+cotA) (cosecA-cotA)= 1

(cosecA+cotA)=1/2

Now,

cosecA-cotA=2

cosecA+cotA=1/2

2cosecA= 2+1/2

cosecA = 5/4

cotA= -3/4

sinA = 1/cosecA =4/5

cosA = 3/5

Now,

2cotA - 5cosA + sinA

=2(-3/4) - 5(3/5) + 4/5

= -37/10

Answer 2

Answer:

Step-by-step explanation:

tep-by-step explanation:

cosecA-cotA = 2

we know,

cosec²A - cot²A = 1

(cosecA+cotA) (cosecA-cotA)= 1

(cosecA+cotA)=1/2

Now,

cosecA-cotA=2

cosecA+cotA=1/2

2cosecA= 2+1/2

cosecA = 5/4

cotA= -3/4

sinA = 1/cosecA =4/5

cosA = 3/5

Now,

2cotA - 5cosA + sinA

=2(-3/4) - 5(3/5) + 4/5

= -37/10