If cosec A= root2 then find the value of 2 sin^2 A+ 3 cot^2A /4 tan^2A - cos^2 A
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HEYA!!
cosecA=√2=cosec45°
A=45°
2sin²A+3cot²2A/4tan²A-cos²2A
=2sin²45°+3cot²2*45°/4tan²45°-cos²2*45°
=2(1/√2)²+3cot²90°/4*(1)²-cos²90°
=2*1/2 + 3*0/4-0
=1+0/4-0
=1/4
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The answer is 8/7
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