if cosec A= secA then the value of 2 tan A+1 is
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2 tan A + 1 =
tanA = sinA/cosA
sinA = 1/cosecA
cosA = 1/secA
1/cosecA
_________ = secA/cosecA
1/secA
Hence tanA = secA/cosecA
since (secA = cosecA)
secA/secA
Hence substitute value of tan in the first equation
2xsecA/secA + 1 = 2+1 = 3
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