Question

if cosec a=sq. root 5. Find hypotenuse, base and perpendicular

Answer 1

$\csc(a) = \sqrt{5} = \frac{h}{b} \\ \\ h \: = \sqrt{5} \\ \\ b \: = 1 \\ \\ h {}^{2} = b {}^{2} + p {}^{2} \\ \\ p = \sqrt{h {}^{2} - b {}^{2} } \\ \\ p \: = \sqrt{5 - 1} \\ \\ p \: = \sqrt{4} \\ \\ p \: = + 2$

Answer 2

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