Question

If cosec A = under root 10, then Find the other five trigonometric ratios.

Answer 1

Hey mate!

cosec x= root 10

cosec²x=10 now sin²x=1/cosec²x

so...sinx= 1/root10

so..sin²x=1/10

then sin²x+cos²x=1

so.....cos²x=1-sin²x

cos²x=1-1/10

=9/10 so...

cos x=3/root 10

tan x =sin x/cos x

=1/root 10/3/root 10=3

sec²x=1/cos²x=1/9/10=10/9

sec x=root 10/3

cot²x=cos²x/sin²x=9/10/1/10=1/9

so....cot x=1/3

hope it helps uu .....

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