If cosec A = under root 5, evaluate (i) 2+(1/sin²A) - (cos²A/sin²A) (ii) 2-sin²A - cos²A
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Answer:
The value of 2−sin
2
θ−cos
2
θ is 1
Step-by-step explanation:
\textbf{Given:}Given:
cosec\,\theta=\sqrt{5}cosecθ=
5
\text{Now}Now
2-sin^2\theta-cos^2\theta2−sin
2
θ−cos
2
θ
=2-(sin^2\theta+cos^2\theta)=2−(sin
2
θ+cos
2
θ)
\text{Using}Using
\boxed{sin^2A+cos^2A=1}
sin
2
A+cos
2
A=1
=2-(1)=2−(1)
=1=1
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