Question

If cosec alpha , cot alpha are the roots of ax2 + bx + c = 0
then

needed the answer in negligible time​

Answer 1

Answer:

Step-by-step explanation:

If cosec alpha , cot alpha are the roots of ax2 + bx + c = 0

=> (x - Cosecα)(x - Cotα) = 0

=> (x  - 1/Sinα)(x - Cosα/Sinα) = 0

=> (xsinα -1)(xsinα - Cosα) = 0

=> x²Sin²α  -xSinα(Cosα + 1) + Cosα = 0

Comparing with ax² + bx + c = 0

a = Sin²α

b = - Sinα(1 + Cosα)

c = Cosα

Answer 2

Answer:

Step-by-step explanation:

If cosec alpha , cot alpha are the roots of ax2 + bx + c = 0

=> (x - Cosecα)(x - Cotα) = 0

=> (x - 1/Sinα)(x - Cosα/Sinα) = 0

=> (xsinα -1)(xsinα - Cosα) = 0

=> x²Sin²α -xSinα(Cosα + 1) + Cosα = 0

Comparing with ax² + bx + c = 0

a = Sin²α

b = - Sinα(1 + Cosα)

c = Cosα