If cosec B =15 /11 find the all remaining trigonometry ratio
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Answer:
if cosecB = 15/11
h/p= 15/11
or, h=15, p=11
now,
b= √h^2-p^2
b=√15^2-11^2
b=√ 225-121
b=√104
b=√13*2*2*2
b= 2√26
then,
sin= p/h = 11/15
cos= b/h = 2√26/15
tan= p/b = 11/2√26
sec= h/b = 15/ 2√26
cot= b/p =2√26/11
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