Math, asked by snehilrohilla90, 3 months ago

If cosecθ - cot θ = 1/2, 0 < θ < π/2, then cosec θ + cot θ =​

Answers

Answered by muskanperween225
0

Step-by-step explanation:

Given, Cosec theta - cot theta =1/2.

Cosec^2 theta - cot^2theta = 1

(Cosec theta + cot theta) (Cosec theta - cot theta) =1

(Cosec theta + Cot theta) * 1/2=1

(Cosec theta + cot theta) = 1* 2

(Cosec theta + cot theta) =2

Answered by nishtha3298
0

Answer:

Given, Cosec theta - cot theta =1/2.

Cosec^2 theta - cot^2theta = 1

(Cosec theta + cot theta) (Cosec theta - cot theta) =1

(Cosec theta + Cot theta) * 1/2=1

(Cosec theta + cot theta) = 1* 2

(Cosec theta + cot theta) =2

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