Question

If cosec ø -sin ø = m and sec ø-cos ø = n prove that (m²n)⅔ + (n²m)⅔ = 1​

Answer 1

Answer:

refer to the attachment for the solution.

Step-by-step explanation:

formula used: sin²∅ + cos²∅ = 1

$\csc( \alpha ) = \frac{1}{ \sin( \alpha ) } \\ \sec( \alpha ) = \frac{1}{ \cos( \alpha ) } .$