If cosec square ( 1+cos ∅) (1 - cos∅ ) = x then find the value of x
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6
Cosec^2(1+cos)(1_cos)
(1/sin^2)(1-cos^2)
(1/sin^2)(sin^2)
1/1
1
Hence x=1
(1/sin^2)(1-cos^2)
(1/sin^2)(sin^2)
1/1
1
Hence x=1
Answered by
0
Answer:
Cosec^2(1+cos)(1_cos)
(1/sin^2)(1-cos^2)
(1/sin^2)(sin^2)
1/1
1
Hence x=1
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