Question

if cosec tetha = 41/40, find sin tetha sec tetha​

Answer 1

Answer:

Sin θ = $\frac{40}{41}$

Sec θ = $\frac{41}{9}$

Step-by-step explanation:

cosec θ $= \frac{1}{sin}$

Therefore;

$\frac{41}{40}=\frac{1}{sin} \\\\\therefore sin = \frac{40}{41}$

As 9,40,41 form pythagorean triplet , the opposite side is 40 , hypotenuse = 41    and the perpendicular \ adjacent side = 9cm

Cos θ = $\frac{adjacent}{hypotenuse}$

Cos θ = $\frac{9}{41}$

Sec θ = $\frac{1}{cos}$

Sec θ = $\frac{41}{9}$

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Answer 2

Answer:

sin theta=p/h=40/41

and sec theta =h/b=41/9

Step-by-step explanation:

cosec theta=H/P

 so, here H=41, P=40

   also, in right angled triangle-  H²=P²+B²

 after putting values of H and P we can find B

 ( 41)²=(40)²+b²

b²=1600

b=9

the, sin theta=p/h=40/41

and sec theta =h/b=41/9