If cosec theata=5/3 then sec theata=
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given cosecA = 5/3 = hyp/opp
do by Pythagorean theorem, adjacent side = 4
so secA = hyp/adj = 5/4
do by Pythagorean theorem, adjacent side = 4
so secA = hyp/adj = 5/4
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» cosec∅ = 5/3
sec∅ =?
we know that,
cosec∅= H/P = 5/3
so,
H= 5
P = 3
now,
from Pythagoras law,
H²= P²+B²
=> 5²= 3²+B²
=>√25-9=B
=> √16 = B
=> 4 = B
we found B = 4
we kow that,
sec∅ = H/B
sec∅ = 5/4
_____________________________
sec∅ =?
we know that,
cosec∅= H/P = 5/3
so,
H= 5
P = 3
now,
from Pythagoras law,
H²= P²+B²
=> 5²= 3²+B²
=>√25-9=B
=> √16 = B
=> 4 = B
we found B = 4
we kow that,
sec∅ = H/B
sec∅ = 5/4
_____________________________
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