if cosec theata - cot theata = 3 then cosec theata + cot theata = ?
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Answered by
0
Step-by-step explanation:
cscθ+cotθ=3...(given)
\cotθ = 3 - \cscθcotθ=3−cscθ
Squaring both sides,
\cot^{2} θ = {(3 - \cscθ) }^{2}cot
2
θ=(3−cscθ)
2
\cot^{2}θ = 9 - 6 \cscθ + { \csc }^{2} θcot
2
θ=9−6cscθ+csc
2
θ
\cot^{2} θ - \csc^{2} θ = 9 - 6 \cscθcot
2
θ−csc
2
θ=9−6cscθ
- 1 = 9 - 6 \cscθ−1=9−6cscθ
6 \cscθ = 106cscθ=10
\cscθ = \frac{5}{3}cscθ=
3
5
\sinθ= \frac{3}{5}sinθ=
5
3
∴ \cosθ = \frac{4}{5}∴cosθ=
5
4
Answered by
0
Step-by-step explanation:
cosec theta - cot theta = 3
On multiplying both side by cosec theta + cot theta
cosec²theta - cot²theta = 3 ( cosec theta + cot theta)
As cosec²theta - cot²theta = 1 Therefore
As cosec²theta - cot²theta = 1 Therefore 1/3 = cosec theta + cot theta Ans
This is the simplest way Thank you
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