Math, asked by gurprabh055, 19 days ago

if cosec theta = √10 find the value of sec theta + 1 ÷ cot theta​

Answers

Answered by at9092193
0

Answer:

By Pythagoras Theorem: AC2 = AB2 + BC2 = 10k2 + k2 = 9k2 AC = 3k Find other T-rations using their definitions: Sin θ = BC/AB = 1/√10 cos θ = AC/AB = (3k)/(k√10) = 3/√10 tan θ = BC/AC = sin θ /cos θ = 1/3 sec θ = AB/AC = 1/cos θ = √10/3 cot θ = AC/BC = 1/tan θ = 3Read more on Sarthaks.com - https://www.sarthaks.com/710670/if-cosec-10-the-find-the-values-of-all-t-ratios-of

Answered by meghanasriram4
0

Answer:

Given function:

cosec θ = √10

Draw a right ∆ABC,

∠C = 90 degrees and ∠A = θ

We know that,

cosec θ = AB/BC = hypotenuse/perpendicular = (k√10)/k (where k is a positive)

By Pythagoras Theorem:

AC2 = AB2 + BC2

= 10k2 + k2 = 9k2 AC = 3k

Find other T-rations using their definitions:

Sin θ = BC/AB = 1/√10

cos θ = AC/AB = (3k)/(k√10) = 3/√10

tan θ = BC/AC = sin θ /cos θ = 1/3

sec θ = AB/AC = 1/cos θ = √10/3

cot θ = AC/BC = 1/tan θ = 3

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