if cosec theta = 13 /12 , find the value of :-
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I hope it help you..
Plz mark me as brainliest..
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Kripa1311:
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cosec theta = 13/12
sin theta = 12 /13---(1)
cos theta = √1-sin² theta
= √1- (12/13)²
= √1- 144/169
= √(169-144)/169
=√25/169
= 5/13
therefore sin theta = 12/13, cos theta =5/13
(2sin theta -3 cos theta) /(4sin theta -9 cos theta)
= (2*12/13 - 3*5/13) /(4*12/13 - 9* 5/13)
=( 24/13 - 15/13)/ (48/13 - 45/13)
= [(24-15)/13]/[(48-45)/13]
=9/3
=3
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