If cosec theta = 2, show that ( cot theta + sin theta / 1 + cos theta ) = 2
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If cosec θ= 2 show that (cot θ + sin θ / 1 + cos θ) = 2
Let us consider a right ∆ABC, right angled at B and ∠C = θ. Now, it is given that cosec θ = 2
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