Question

If Cosec theta =3/2 then 2(cosec.^2 theta +cot^theta)=​

Answer 1

Step-by-step explanation:

We know by identity

$1 + {cot}^{2} theta \: = {cosec}^{2} theta$

Using this

${cot}^{2} theta = {(3 \div 2)}^{2} - 1$

${cot}^{2} theta = 5 \div 4$

$cot \: theta = \sqrt{5} \div 2$

Now according to question

$2( {cosec}^{2} theta + {cot}^{2} \: theta)$

2(9/4+5/4)

2*14/4

7 is the answer

Answer 2

Answer is 7

• explanation :

1. given that : cosec theta = 3/2
2. 2 ( cosec ^2 theta + cot^2theta ) = 2( cosec ^ 2 + cosec^2 - 1 ).
3. 2( 2× 3/2 ^2 -1 -1 ).
4. 2( 2 × 9/4 -1 ).
5. 2 (9/2 )-1.
6. 2 × 7/2 = 7