If cosec theta =3/2
then find 2(cosec²theta+ cot²theta A).
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wkt, cosec²@-cot²@=1
=>cot²@= 1+cosec²@
2(cosec²@+cot²@)
=2(cosec²@+cosec²@+1)
=2[(3/2)²+(3/2)²+1]
=2(9/8+ 9/8 +1)
= 2[(9+9+8)/8]
= 2(26/8)
= 26/4
= 13/2
hope it helps u......^_^
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