Math, asked by mathivanan4, 10 months ago

If cosec theta =3/2
then find 2(cosec²theta+ cot²theta A).
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Answered by Ishwarya12
0

Answer:

wkt, cosec²@-cot²@=1

=>cot²@= 1+cosec²@

2(cosec²@+cot²@)

=2(cosec²@+cosec²@+1)

=2[(3/2)²+(3/2)²+1]

=2(9/8+ 9/8 +1)

= 2[(9+9+8)/8]

= 2(26/8)

= 26/4

= 13/2

hope it helps u......^_^

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