if cosec theta=3x and cot theta=3/x, then find the value of (x²-1/x²)
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Answered by
43
cosectheta=3x
x=cosectheta/3
cottheta=3/x
1/x =cotheta/3
x^2-1/x^2
(cosectheta/3)^2 -(cottheta/3)^2
cosec^2theta/9 -cot^2theta/9
cosec^2theta-cot^2theta/9
1/9 is answer obtained
x=cosectheta/3
cottheta=3/x
1/x =cotheta/3
x^2-1/x^2
(cosectheta/3)^2 -(cottheta/3)^2
cosec^2theta/9 -cot^2theta/9
cosec^2theta-cot^2theta/9
1/9 is answer obtained
Answered by
65
Hope it helpful......
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arushisaini1530:
Thnxu....I understand...properly.....
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