Question

if cosec theta=5/3, find the value of five other trigonometric ratios.​

Answer 1

Answer:

$\csc( \alpha ) = \frac{5}{3}$

H^2=P^2+ B^2

(5) ^2= (3) ^2+ B^2

25=9+(B) ^2

25-9=(B) ^2

16=(B) ^2

$b = \sqrt{16} \\ b = 4$

sin=P/H

------>3/5

cos=b/H

------> 4/5

tan=p/b

-------> 3/4

cosec=h/P

------> 5/3

sec=h/b

------> 5/4

Step-by-step explanation:

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