if cosec theta-cot theta= 1by 3,then
cosec theta +Cot theta =?
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Given,
cosec theeta - cot theeta = 1/3
cosec² theeta = 1 + cot² theeta
=> cosec² theeta - cot² theeta = 1
=> ( cosec theeta - cot theeta ) ( cosec theeta + cot theeta ) = 1
=> { 1 × ( cosec theeta + cot theeta ) } / 3 = 1
=> cosec thetha + cot theeta = 1 × 3
=> cosec theeta + cot theeta = 3
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