If Cosec theta + Cot theta = K then Prove that Sec theta = K2+1/K2-1
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Step-by-step explanation:
Given,
cosecθ+cotθ=k
sinθ1+sinθcosθ=k
sinθ1+cosθ=k
1+cosθ=ksinθ
Squaring both side,
(1+cosθ)2=k2sin2θ
(1+cosθ)2=k2(1−cos2θ)
(1+cosθ).(1+cosθ)=k2(1+cosθ)(1−cosθ)
1+cosθ=k2(1−cosθ)
1+cosθ=k2−k2cosθ
1+(1+k2)cosθ=k2
(1+k2)cosθ=k2−1
cosθ=k2+1k2−1
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