If cosec theta - cot theta = q, then the value of cot theta is
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.....cosecΦ–cotΦ=q
cotΦ= cosecΦ–q
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Step-by-step explanation:
Given : cosecθ−cotθ=q
We know that 1+cot2θ=cosec2θ
∴1+cot2θ−−−−−−−−√−cotθ=q
⇒1+cot2θ−−−−−−−−√=q+cotθ
Squaring both sides, we get
∴(1+cot2θ)=(q+cotθ)2
⇒1+cot2θ=q2+cot2θ+2qcotθ
⇒1−q2=2qcotθ
⇒cotθ=1−q22q
hope it helps you
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