if cosec theta is equal to 13 by 12 find the value of 2 sin theta minus 3 cos theta upon 4 sin theta minus cos theta
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let, theeta =x.
then according to the question,
cosec x=13/12
1/sin x=13/12
sin x=12/13
sin²x+cos²x=1
cos²x=1-sin²x=1-(12/13)²=25/169
cos x=5/13
(2sin x-3cos x)/4sin x-cos x
={(2*12/13)-(3*5/13)} / {(4*12/13)-(5/13)}
={(24-15)/13} / {(48-5)/13}
=9/43
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