Math, asked by Rpsingh7800, 6 months ago

if cosec theta is equal to 13 by 12 find the value of 2 sin theta minus 3 cos theta upon 4 sin theta minus cos theta​

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Answered by jiyasharma77
0

this is your answer

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Answered by souvikghosh738
0

Answer:

let, theeta =x.

then according to the question,

cosec x=13/12

1/sin x=13/12

sin x=12/13

sin²x+cos²x=1

cos²x=1-sin²x=1-(12/13)²=25/169

cos x=5/13

(2sin x-3cos x)/4sin x-cos x

={(2*12/13)-(3*5/13)} / {(4*12/13)-(5/13)}

={(24-15)/13} / {(48-5)/13}

=9/43

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