Question

If cosec theta=root10,then sec theta =?

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

let theta be x

cosec x= √10 /1 = h/p

1^2 + b^2 = √10^2

1 + b^2 = 10

b^2 = 10 - 1

b^2 = 9

b = √9

b =3

sec x = √10/ 3