If cosec theta-sin theta=4 then sin^2theta+cosec^2theta=
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Answered by
10
Hi Mate!!!
Squaring both sided
{Cosec ( x ) - Sin ( x ) }² = 16
=>. Sin² ( x ) + Cosec² ( x ) = 16 +2
=>. Sin² ( x ) + Cosec ² ( x ) = 18
Have a nice time
Squaring both sided
{Cosec ( x ) - Sin ( x ) }² = 16
=>. Sin² ( x ) + Cosec² ( x ) = 16 +2
=>. Sin² ( x ) + Cosec ² ( x ) = 18
Have a nice time
Answered by
0
Step-by-step explanation:
Answer
Given sinθ+cosecθ=2
⟹sinθ+sinθ1=2
squaring on both sides
(sinθ+sinθ1)2=4
⟹sin2θ+sin2θ1+2(sinθ)(sinθ1)=4
⟹sin2θ+sin2θ1+2=4
⟹sin2θ+sin2θ1=2
⟹sin2θ+cosec2θ=2
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