Question

If COSEC theta-sin theta= a and
sec theta -cos theta = b
Prove
a^2b^2(a^2+b^2+3)=1​

Answer 1

Answer:

......

Step-by-step explanation:

Cosec Theeta - Sin Theeta = a

1/Sin Theeta - Sin Theeta = a

1- Sin^2 Theeta/Sin Theeta = a

Cos^2 Theeta = a Sin Theeta (1)

SIMILARLY,

Sin^2 Theeta = b Cos Theeta (2)

ADDING (1),(2)

1 = a Sin Theeta + b Cos Theeta

The question is incomplete

Actualy, To prove is wrong