Question

If cosec thetha=13/5.find tan thetha and cot thetha​

Answer 1

Step-by-step explanation:

Given that,

cosec theta= 13/5

So, Hypotenuse= 13 cm

Perpendicular= 5 cm

Base= 12 cm (By Pythagoras Theorem)

Now, tan theta= Perpendicular/Base

= 5/12

And, cot theta= Base/Perpendicular

= 12/5

Answer 2

Step-by-step explanation:

Given

$\cosec \theta = \frac{13}{5}$

H = 13

P = 5

B = ?

By using pytagoras theroem. .

${H }^{2} = {</p><p>P }^{2} + {B}^{2} </p><p>$

${13}^{2} = {5}^{2} + {B}^{2}$

$169 - 25 = {B}^{2}$

$144 = {B}^{2}$

$B = \sqrt{144}$

$B = 12$

Therefore,

$\tan \theta = \frac{p}{b} = \frac{5}{12}$

And

$\cot \theta = \frac{b}{p} = \frac{12}{5}$

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