if cosec thita = 2x and cot thita = 2/x , find the value of 2( x square - 1/x square )
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x=(1/2)cosec theta, 1/x =(1/2)cot theta
x^2 = (1/4) cosec^2 theta
(1/x)^2=(1/4)cot^2 theta
2(x^2- (1/x)^2 )= 2×(1/4)(cosec^2 theta- cot^2 theta)=2×(1/4)×(1) = 1/2Ans
sahaditipriya0:
thanks
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