If cosec x + cot x = a, then the value of cos x is
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cosec x +cot x = a --------------(1)
we know that
cosec^2 x -cot^2 x = 1
(cosec x +cot x)(cosec x -cot x) = 1
a(cosec x-cot x) = 1
(cosec x-cot x) = 1/a ------------------(2)
from (1) & (2)
cosec x+cot x = a
cosec x-cot x = 1/a
2cosec x = a+1/a
2cosec x= a^2+1/a
cosec x = a^2+1/2a
sin x = 2a/a^2+1
we know that
cos x = √1-sin^2 x
cos x = √1-[2a/a^2+1]^2
cos x = √1-4a^2/(a^2+1)^2
cos x = √(a^2+1)^2-4a^2/(a^2+1)^2
cos x = √(a^2-1)^2/(a^2+1)^2 {·(a+b)^2-(a-b)^2 = 4ab}
cos x = √[a^2-1/a^2+1]^2
Step-by-step explanation:
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