If cosec²θ (1 + cos θ) (1 − cos θ) = λ, then find the value of λ.
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The value of λ is 1 .
Step-by-step explanation:
Given : cosec²θ (1 + cos θ) (1 − cos θ) = λ
cosec²θ [(1 + cos θ) (1 − cos θ)] = λ
cosec²θ (1 − cos² θ) = λ
[By using identity , (a + b) (a - b) = a² - b²]
cosec² θ (1 − cos² θ) = λ
cosec² θ (sin² θ) = λ
[By using the identity, (1 - cos²θ) = sin²θ]
1/sin²θ × sin²θ = λ
[cosecθ = 1/ sinθ]
1= λ
λ = 1
Hence, the value of λ is 1 .
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