If cosecA =2;then find the values of cos A and tan A
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cosecA=2
sinA=1/2
cos2A= 1-1/4 =3/4
cosA=(3)^1/2 /2
tanA=3^1/2
sinA=1/2
cos2A= 1-1/4 =3/4
cosA=(3)^1/2 /2
tanA=3^1/2
SangralNeha111:
Cosec A=2sinA=1/2COS 2A=1-1/4=3/4cos A=(3)^1/2 Tan=3^1/2
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CosecA=2/1 = x (let)
Then;
(2x)^2-(1x)^2=AB^2 (Pythagoras theoram)
AB=1x
CosA = base /hypotenuse
=1x/2x x would be cut so ans is 1/2
TanA= perpendicular/base
=1x/1x x would cut and the ans is 1 or 1/1
Then;
(2x)^2-(1x)^2=AB^2 (Pythagoras theoram)
AB=1x
CosA = base /hypotenuse
=1x/2x x would be cut so ans is 1/2
TanA= perpendicular/base
=1x/1x x would cut and the ans is 1 or 1/1
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