If cosecA-cotA=11/2,then tanA=
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Answered by
15
1/ sinA - cosA / SinA
= 1- cosA / sin A =11/2
= 2sin²A/2 /2sinA/2 CosA/2
tanA/2=11/2
sinA/2 = 11/5√5
cosA/2= 2/5√5
Now sinA=2*11/5√5*2/5√5= 44/125
CosA =√1-1936/15625
=√15625-1936/15625
=√13689/15625
=117/125
so now
tanA=sinA/cosA = 44/117
hope helped ^!!
= 1- cosA / sin A =11/2
= 2sin²A/2 /2sinA/2 CosA/2
tanA/2=11/2
sinA/2 = 11/5√5
cosA/2= 2/5√5
Now sinA=2*11/5√5*2/5√5= 44/125
CosA =√1-1936/15625
=√15625-1936/15625
=√13689/15625
=117/125
so now
tanA=sinA/cosA = 44/117
hope helped ^!!
Answered by
10
heya
cosec A + cot A = 11/2 ... (1)
(cosec A + cot A) x (cosec A - cot A)/(cosec A - cot A) = 11/2
(cosec^2 A - cot^2 A) /(cosec A - cot A ) = 11/2
Now cosec^2 A - cot^2 A = 1
Therefore, 1/(cosecA - cotA) = 11/2
cosec A - cot A = 2/11 ... (2)
From (1) and (2), we get,
- 2 cot A = 2/11 -11/2 = -117/22
cot A = 117/44
Therefore, tan A = 1/cot A = 44/117
cosec A + cot A = 11/2 ... (1)
(cosec A + cot A) x (cosec A - cot A)/(cosec A - cot A) = 11/2
(cosec^2 A - cot^2 A) /(cosec A - cot A ) = 11/2
Now cosec^2 A - cot^2 A = 1
Therefore, 1/(cosecA - cotA) = 11/2
cosec A - cot A = 2/11 ... (2)
From (1) and (2), we get,
- 2 cot A = 2/11 -11/2 = -117/22
cot A = 117/44
Therefore, tan A = 1/cot A = 44/117
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