Math, asked by Lalettan, 1 year ago

If cosecA-cotA=11/2,then tanA=

Answers

Answered by HappiestWriter012
15
1/ sinA - cosA / SinA

= 1- cosA / sin A =11/2

= 2sin²A/2 /2sinA/2 CosA/2

tanA/2=11/2

sinA/2 = 11/5√5

cosA/2= 2/5√5

Now sinA=2*11/5√5*2/5√5= 44/125

CosA =√1-1936/15625

=√15625-1936/15625

=√13689/15625

=117/125

so now

tanA=sinA/cosA = 44/117

hope helped ^!!
Answered by Deekshii1
10
heya

cosec A + cot A = 11/2            ... (1)

(cosec A + cot A) x (cosec A - cot A)/(cosec A - cot A) = 11/2
(cosec^2 A - cot^2 A) /(cosec A - cot A ) = 11/2
Now cosec^2 A - cot^2 A = 1
Therefore, 1/(cosecA - cotA) = 11/2

cosec A - cot A = 2/11             ... (2)
From (1) and (2), we get,
- 2 cot A = 2/11 -11/2 = -117/22
cot A = 117/44
Therefore, tan A = 1/cot A = 44/117

 

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