Question

If coseco-coto=2017. then quadrant in which is​

Answer 1

Answer:

Step-by-step explanation:

$cosecA-cotA=2017\\=>(cosecA-cotA)^2=2017^2\\=>cosec^2A +cot^2A-2.cosecA.cotA =4068289\\=>1+cot^2A+cot^2A-2.cosecA.cotA=4068289\\=>2cotA(cotA-cosecA))=4068288\\=>cotA(cotA-cosecA))=2034144\\=>2017cotA =2034144\\=>cotA=1008.5\\=>tanA=0\\=>A=0$

A=0°

So, A lies in the first quadrant