Question

if Cosecø - Sinø = A³ , Secø-Cosø = b³ prove that a²b²(a²+b²)=1 ..... i need the answer in copy and specially in the step how Cos4/3ø×Cos2/3ø+Sin4/3ø×Sin2/3ø = Cos²ø+Sin²ø... i need a step by step cancellation process don't copy it from google its an request
;-) ​

Answer 1

Answer: Hi Dear your Question is incomplete

the complete question is Cosec∅ - sin∅ = a, Sec∅ - cos∅ = b

prove a²b²(a²+b²+3) so solve this difficult question we will follow these steps.

Step-by-step explanation:

from LHS   a²b²(a²+b²+3)

Put the value of a and b in LHS.

( cosec∅ - sin∅)²(sec∅ - cos∅)²{(cosec∅ - sin∅)²+(sec∅ - cos∅)²+3}

(1/sin∅ - sin∅)²(1/cos∅ - cos∅)²{(1/sin∅ - sin∅)²+(1/cos∅ - cos∅)²+3}

(1 - sin²∅/sin∅)²(1 - cos²∅/cos∅)²{(1 - sin²∅/sin∅)²+(1 - cos²∅/cos∅)²+3}

(cos²∅/sin∅)²(sin²∅/cos∅)²{((cos²∅/sin∅)²+(sin²∅/cos∅)²+3}

rest will be tomorrow....