if cosectheta=t+1/4t(t not included in fraction), then prove that cosectheta + cottheta = 2t or 1/2t
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Answered by
1
√{(sec β -1)/(secβ +1)}
= √{(1 - cosβ)/(1+cosβ)} (by dividing every term by secβ
= √{(1-cosβ)²/(1-cos²β)} ( by multiplying numerator & denominator by (1-cosβ)
= √{(1- cosβ)² / sin²β }
= (1-cosβ) / sinβ …………………. (1)
Similarly, √{(secβ +1)/(secβ -1)
= √{(1+cosβ) / (1-cosβ) } ( as done above)
= √{(1+cosβ)² / (1-cos²β) }
= √{(1+cosβ)² / sin² β }
= (1+cosβ ) / sinβ ……………. (2)
By adding (1) & (2)
LHS =
= { 1-cosβ + 1+cosβ } / sinβ
= 2/sinβ
= 2 cosec β
= RHS
[ Hence proved]
Answered by
5
Underoute {( sec B)/ (Sec B + 1)}
= Underoute {( 1 - cos B)Square/ (1 - Cos Square B)} ( By Multiplying numerator and denominator by (1 - Cos B)
= Unteroute (1 - Cos B) Square /Sin Square B)
(1 - Cos B)/ Sin B.............. (1)
Similarly, Underoute {(Sec B+ 1/ Sec B - 1)
= Underoute {( 1+ Cos B/(1- Cos B)} ( As Done above)
= Underoute {(1+ Cos B) Square/ Sin Square B)
= Underoute {(1+ Cos B)/ Sin B........... (2)
By adding (1) & (2)
LHS =
= ( 1- Cos B + 1+ Cos B)/ Sin B
= 2 Cosec B
= RHS
Hence, Proved.
= Underoute {( 1 - cos B)Square/ (1 - Cos Square B)} ( By Multiplying numerator and denominator by (1 - Cos B)
= Unteroute (1 - Cos B) Square /Sin Square B)
(1 - Cos B)/ Sin B.............. (1)
Similarly, Underoute {(Sec B+ 1/ Sec B - 1)
= Underoute {( 1+ Cos B/(1- Cos B)} ( As Done above)
= Underoute {(1+ Cos B) Square/ Sin Square B)
= Underoute {(1+ Cos B)/ Sin B........... (2)
By adding (1) & (2)
LHS =
= ( 1- Cos B + 1+ Cos B)/ Sin B
= 2 Cosec B
= RHS
Hence, Proved.
ViratKohli3618:
Plx.. More Thanks
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