if cosectheta theta =2 and cot theta =root 39 where theta is an acute angle, find the value of p
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cosec @ = h/p = 2/1
By using Pythagoras theorem,
b = √(h^2 - p^2)
b = √(2)^2 - (1)^2
b = √(4-1)
b = √3
Now cot @ = b/p = √3/1
It is given cot @ = √3p
√3p = √3/1
p = 1
So your required answer is B) 1
Hope This Helps You!
By using Pythagoras theorem,
b = √(h^2 - p^2)
b = √(2)^2 - (1)^2
b = √(4-1)
b = √3
Now cot @ = b/p = √3/1
It is given cot @ = √3p
√3p = √3/1
p = 1
So your required answer is B) 1
Hope This Helps You!
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