Question

if Cosecx=1+ Cotx & then x =

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Answer 1

Step-by-step explanation:

$\cosec(x) = 1 + \cot(x) \\ squaring \: \: both \: \: side \\ cosec {}^{2} x = (1 + \cot(x)) {}^{2} \\ \\ cosec{}^{2} x = 1 + cot {}^{2} x + 2cot x \\ \\we \: \: \: know \: \: \: that \\ (1 + cot {}^{2} x = cosec{}^{2} x) \\ \\ cosec{}^{2} x = cosec{}^{2} x + 2 cot {}^{2} x \\ \\ 2cot {x}^{2} = 0 \\ \\ cotx = 0 \\ x = \frac{\pi}{2} \\ or \: \\ \\ x = \frac{\pi}{2} + n\pi$

Answer 2

Answer:

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