Question

If cosecx + cotx = 11/2 then sinx=?​

Answer 1

Step-by-step explanation:

cosec A + cot A = 11/2,

cosec A = 11/2 - cot A. (Squaring both sides)

cosec^2 A = 121/4 -11 cot A + cot^2 A

cosec^2 A = 117/4 -11 A +1+ cot^2 A

cosec^2 A -(1- cot^2 A)=117/4 -11 cot A [cosec^2 A is the same as(1- cot^2 A)]

0 =117/4 -11 cot A, or

cot A = 117/44,

by Pythagoras theorem,

hypo=√perpendicular^2+base^2

=√(117)^2+(44)^2

=√13689+1936

=√15625

=125

therefore,

sinA=per/hypo

=44/125

hope my answer will satisfy you....

Answer 2

Answer:

Step-by-step explanation: