Question

if cosecx-sinx=m and secx-cosx=n then find m^2n^2(m^2+n^2+3)​

Answer 1

Answer:

1

Step-by-step explanation:

m^2n^2(m^2+n^2+3)​ =  m²n²(m²+n²+3)​

= (cosecx-sinx)²( secx-cosx)²{(cosecx-sinx)² + ( secx-cosx)² +3}

= (cosec²x -2 + sin²x)( sec²x-2 + cos²x) {(cosec²x + sec²x }

= (cosec²x -2 + sin²x)( sec²x-2 + cos²x) {(cosec²x  sec²x }

=  (cosec²x-1)²( sec²x-1)²

= (cot²x)²(tan²x)²

= 1