if cosesФ=√5,find the value of cotФ(whereФis acute
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bakkulu:
sorry with formula
cosecX=sqrt. of 5
so...cosec^2=5
we know....1+cot^2=cosec^2
ok????understood?
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CosecФ=√5,
cosecФ=hypotenuse /opp side
Therefore hypotenuse =√5,oppside=1,adjcent side =2
cot Ф=Adj side /opp side=2/1=2 is the answer
cosecФ=hypotenuse /opp side
Therefore hypotenuse =√5,oppside=1,adjcent side =2
cot Ф=Adj side /opp side=2/1=2 is the answer
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