If coso =root 3 upon 2 . Find sino, tano
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cos0=root3/2
base=root3k
hypotenuse =2k
by perpendicular theorum
b²+p²=h²
(root3k)²+p²=2²k²
p²=4k²-3k²
p²=k²
p=k
sin0=p/h
=1/2
tan0=p/b
=1/root3
base=root3k
hypotenuse =2k
by perpendicular theorum
b²+p²=h²
(root3k)²+p²=2²k²
p²=4k²-3k²
p²=k²
p=k
sin0=p/h
=1/2
tan0=p/b
=1/root3
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