Question

if Coso + Sino-V2coso, then coso-sino​

Answer 1

Question: If cos θ + sin θ = √2cos θ , then prove that cos θ - sin θ = √2sin θ

Step-by-step explanation:

Given

cos θ + sin θ = √2cos θ

Squaring both side, we get

(cos θ + sin θ)2 = 2cos2θ

cos2θ + sin2θ + 2 × cosθ × sinθ = 2cos2θ

sin2θ + 2 × cosθ × sinθ = 2cos2θ – cos2θ

sin2θ + 2 × cosθ × sinθ = cos2θ

cos2θ – 2 × cosθ × sinθ = sin2θ

Now adding sin2θ both side, we get

cos2θ -2 × cosθ × sinθ + sin2θ = sin2θ + sin2θ

(cos θ – sin θ)2 = 2sin2θ

cos θ – sin θ = √2sinθ

∴ cos θ – sin θ = √2sinθ