If cosø = 4/5 and sinø = 3/5 , find the value of sec2ø - tan2ø.
Answers
Answered by
0
Answer:
cosø = 4/5 , sinø = 3/5
sin2ø=2sinøcosø=2×4/5.×3/5=24/25
cos2ø=√(1-sin²2ø) =√(1-576/625=√49/625=7/25
tan2ø=sin2ø/cos2ø=24/25.×25/7=24/7
sec2ø=1/cos2ø=25/7
sec2ø - tan2ø. =25/7 -24/7=1/7
sec2ø - tan2ø. =1/7.
mark as Brainlist answer
Similar questions